dtoolkit.accessor.dataframe.boolean#
- dtoolkit.accessor.dataframe.boolean(df: DataFrame, /, how: Literal['any', 'all'] = 'any', complement: bool = False, **kwargs) Series [source]#
Return whether any (or all) element is True, potentially over an
axis
.An API to gather
any()
andall()
to one.- Parameters:
- how{‘any’, ‘all’}, default ‘any’
Choose a method to get mask.
- axis{0 or ‘index’, 1 or ‘columns’, None}, default 0
Indicate which axis or axes should be reduced.
0 / ‘index’ : reduce the index, return a Series whose index is the original column labels.
1 / ‘columns’ : reduce the columns, return a Series whose index is the original index.
None : reduce all axes, return a scalar.
- complementbool, default False
If True does logical ‘not’ operator to values firstly.
- **kwargs
See the documentation for
any()
andall
for complete details on the keyword arguments.
- Returns:
- Series(bool)
- Raises:
- ValueError
If
how
isn’t “any” or “all”.
See also
Examples
>>> import dtoolkit >>> import pandas as pd >>> df = pd.DataFrame({"a": [True, True, False], "b": [False, True, False]}) >>> df a b 0 True False 1 True True 2 False False
Get the bool value from each column.
>>> df.boolean(how="any") a True b True dtype: bool
Get the bool value from each row. And require each element is True.
>>> df.boolean(how="all", axis=1) 0 False 1 True 2 False dtype: bool
Do a ‘~’ (logical not) operation then get the bool value.
>>> df.boolean(how="all", axis=1, complement=True) 0 False 1 False 2 True dtype: bool
Get the bool value from the entire data.
>>> df.boolean(how="all", axis=None) False